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handle modelnames / permissions with underscores

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Matthias 2021-11-01 00:24:57 +01:00
parent fc566621b7
commit a8e18a7972
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1 changed files with 15 additions and 2 deletions
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17
InvenTree/users/models.py
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@ -234,7 +234,7 @@ class RuleSet(models.Model):
given the app_model name, and the permission type.
"""
app, model = model.split('_')
model, app = split_model(model)
return "{app}.{perm}_{model}".format(
app=app,
@ -277,6 +277,19 @@ class RuleSet(models.Model):
return self.RULESET_MODELS.get(self.name, [])
def split_model(model):
"""get modelname and app from modelstring"""
app, *model = model.split('_')
# handle models that have
if len(model) > 1:
model = '_'.join(model)
else:
model = model[0]
return model, app
def update_group_roles(group, debug=False):
"""
@ -380,7 +393,7 @@ def update_group_roles(group, debug=False):
(app, perm) = permission_string.split('.')
(permission_name, model) = perm.split('_')
(model, permission_name) = split_model(perm)
try:
content_type = ContentType.objects.get(app_label=app, model=model)